Question

evaluate the following for p=-1, Q=-3,r =7: c.) p+q-pq+r^2​

Answer 1

Answer required:

The value of p + q – pq + r² when p = – 1, q = – 3 and r = 7 is 42.

Step-by-step explanation:

The values given are :

• p = – 1

• q = – 3

• r = 7

Let's substitute these values in p + q – pq + r² and find the value :

→ p + q – pq + r²

→ (– 1) + (– 3) – (– 1) (– 3) + ( 7 )²

→ – 1 – 3 – 3 + 49

→ – 7 + 49

→ 42

Therefore, the value of p + q – pq + r² is 42.

Must remember:

While adding, subtracting and doing other operations with integers, the following rules should be followed :

• (–) × (+) = (–)

• (+) × (–) = (–)

• (–) × (–) = (+)

• (+) × (+) = (+)