Evaluate the following:
(i) √2 sin 135º cos 210° tan 240° cot 300° sec 330°
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Step-by-step explanation:
To find :
√2 sin 135º cos 210° tan 240° cot 300° sec 330°
Formula needed:
sin (180°- A) = sinA
cos (180°+ A) = - cosA
tan ( 180° + A) = tanA
cot ( 360° - A) = -cotA
sec (360° - A) = secA
Putting the values in formula :
sin135° = sin (180°- 45) = sin45° = 1/√2
tan240° = tan ( 180° + 60°) = tan60° = √3
cos210° = cos (180°+ 30°) = - cos30° = -√3/2
cot 300° = cot ( 360° - 60°) = - cot60° = -1/√3
sec330° = sec (360° - 30°) = sec30° = 2/√3
Solving:
√2 x (1/√2) x (-√3/2) x (√3) x (-1/√3) x (2/√3)
= 1
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