Question

evaluate the following i^231 where I=√-1​

Answer 1

Step-by-step explanation:

i

231

=(i

4

)

57

×i

2

×i

We know the following

{i}^{2} = - 1i

2

=−1

{i}^{4} = 1i

4

=1

Hence

{i}^{231} = ( {1})^{57} \times ( -1) \times ii

231

=(1)

57

×(−1)×i

{i}^{231} = - ii

231

=−i