Question

evaluate the following i^231 where i=√-1​

Answer 1

Answer:

$- i$

Step-by-step explanation:

${i}^{231} = ( {i}^{4} )^{57} \times {i}^{2} \times i$

We know the following

${i}^{2} = - 1$

${i}^{4} = 1$

Hence

${i}^{231} = ( {1})^{57} \times ( -1) \times i$

${i}^{231} = - i$