Question

Evaluate the following i79

Answer 1

Step-by-step explanation:

i

79

i79

Rewrite

i

79

i79 as

(

i

4

)

19

(

i

2

⋅

i

)

(i4)19(i2⋅i).

Tap for more steps...

(

i

4

)

19

(

i

2

⋅

i

)

(i4)19(i2⋅i)

Rewrite

i

4

i4 as

1

1.

Tap for more steps...

1

19

(

i

2

⋅

i

)

119(i2⋅i)

One to any power is one.

1

(

i

2

⋅

i

)

1(i2⋅i)

Multiply

i

2

⋅

i

i2⋅i by

1

1.

i

2

⋅

i

i2⋅i

Rewrite

i

2

i2 as

−

1

-1.

−

1

⋅

i

-1⋅i

Rewrite

−

1

i

-1i as

−

i

-i.

−

i

-i

Answer 2

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

79/4= 19 remainder 3

Using above knowledge

i79

=(i4)19×i3

=(1)19×i3

=1×i3

=i3

=-i