evaluate the following if a=-2 , b=1 , c=2. (a) 4a^b-3/2ab^2+1/2abc
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Answer:
hy yaari..
Step-by-step explanation:
a = -2 ; b = 1 ; c = 2
4a^b-3/2ab^2+1/2abc
= 4(-2)^1 - 3/2 (-2×1)^2 + 1/2 (-2×1×2)
= -8 - 3/2×4 + 1/2 ×(-4)
= -8-3/8-2
= -10-3/8
= -80-3/8
= -83/8
mark as brainliest yar...
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