Question

evaluate the following integrals

Answer 1

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Answer 2

Answer:

I = ∫1 ÷ √(3 - 4x) dx

 = ∫(3 - 4x)^⁻¹/² dx

 = [(3 -4x)^¹/² ÷ 1/2 ] × (₋ 1/4) + C

∴ I  = - 1/2 (3 -4x)^¹/² + C

Step-by-step explanation: