Math, asked by amitrajmuzaffap39dc9, 1 year ago

evaluate the following integrals

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Answered by visuzuvuli
0

Answer:

-(2x-3)^(-1/2)

Step-by-step explanation:

\int \frac{1}{(2x-3)^{3/2}} dx\\\frac{1}{2} \int (2x-3)^{-3/2} 2dx\\\frac{1}{2} \frac{(2x-3)^{-1/2}}{-1/2}\\-(2x-3)^{-1/2}

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