Question

Evaluate the following:

Iota to the power of 403

Answer 1

Answer:

The answer should be

$- \sqrt{ - 1}$

Step-by-step explanation:

${i}^{403}$

$= (i) {}^{400 + 3}$

$=( i {}^{400}) \times ( {i}^{3} )$

$= ( {i}^{4} ) {}^{100} \times i {}^{3}$

$= (1) {}^{100} \times - \sqrt{ - 1}$

$= 1 \times - \sqrt{ - 1}$

$= - \sqrt{ - 1}$

Hope this helped you.

Thank you.

Answer 2

Answer:

-root -1

is the answer .....

thanks ....❤❤