Question

evaluate the following
Maths:

sin 60° cos 30° + sin 30° cos 60°

​

Answer 1

Step-by-step explanation:

sin 60⁰ cos30⁰+ sin 30⁰ cos 60⁰

(sin a cos b+ cos a sin b=sin(a+b)

=>sin(60⁰+30⁰)=sin 90⁰=1

Answer 2

Solution:-

We have

⇒ sin 60° cos 30° + sin 30° cos 60°

We know that value 0f

$\rm \sin60^{0} =\dfrac{\sqrt{3} }{2}\\ \cos60^{0}=\dfrac{1}{2}\\ \sin30^{0}=\dfrac{1}{2}\\ \cos30^{0} =\dfrac{\sqrt{3} }{2}$

⇒ sin 60° cos 30° + sin 30° cos 60°

Put the value

$\implies\dfrac{\sqrt{3} }{2} \times \dfrac{\sqrt{3} }{2}+\dfrac{1}{2} \times \dfrac{1}{2}$

$\implies\dfrac{3}{4} +\dfrac{1}{4}$

$\implies\dfrac{4}{4} =1$

Answer:- 1

​