Question

Evaluate the following :






Plz Koi to answer de do....
It's urgent ​

Answer 1

see the attachment....... ♥

Answer 2

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➡Given here.

♠sin[ π/3 - (sin^-1(-1/2)].

sin[ π/3 - (sin^-1(-1/2)].= sin[ π/3 + sin^-1(1/2)].

sin[ π/3 - (sin^-1(-1/2)].= sin[ π/3 + sin^-1(1/2)].= Sin[ π/3+ π/3].

sin[ π/3 - (sin^-1(-1/2)].= sin[ π/3 + sin^-1(1/2)].= Sin[ π/3+ π/3].= Sin[ 2π/6].

sin[ π/3 - (sin^-1(-1/2)].= sin[ π/3 + sin^-1(1/2)].= Sin[ π/3+ π/3].= Sin[ 2π/6].= Sin[ π/3].

sin[ π/3 - (sin^-1(-1/2)].= sin[ π/3 + sin^-1(1/2)].= Sin[ π/3+ π/3].= Sin[ 2π/6].= Sin[ π/3].= √3/2.

➡Hopes its helps u.

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