Question

evaluate the following products without actual multiplication (i) 101 *99​

Answer 1

Answer:

Step-by-step explanation:

by using identity

$a^{2} +b^{2}$= (a+b)(a-b)

(100+1)(100-1) = $100^{2} +1^{2}$

                     = 10000+1

                     =10001