evaluate the following products without multiplying dierectly: (104)^3
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3
(i) 103×107
=(100+3)(100+7)
=(100)
2
+(3+7)(100)+(3)(7)
=10000+1000+21=11021
(ii) 95×96
=(90+5)(90+6)=(90)
2
+(5+6)(90)+(5)(6)
=8100+990+30=9120
(iii) 104×96
=(100+4)(100−4)
=(100)
2
−(4)
2
=10000−16=9984
Answered by
2
ye apka answer sehi hain
thank uu..
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