Evaluate the following:(sintheta +costheta)^2+(sintheta-costheta)^2
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(sintheta +costheta)^2+(sintheta-costheta)^2
here the identities (a+b)² and (a-b)² can be used ,
i am going to use 'a ' instead of theta
(sin²a + 2×sin a ×cos a + cos²a) + (sin²a - 2×sin a ×cos a + cos²a)
since , sin²theta + cos²theta =1 . we can write 1 in place of sin²a + cos²a
(1+ 2×sin a ×cos a ) + (1-2×sin a ×cos a)
open the brackets ,
1+ 2×sin a ×cos a + 1 - 2×sin a ×cos a
=2 + 0
=2
hope my answer is helpful :)
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