Evaluate the following:-
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by sum of GP a( r^n - 1) /(r-1)
1/i + 1/i^2 .......+1/i^20 = 1/i(1/i^20-1)/(1/i-1)
since 1/i^20 = 1
thus sum = 1/i (1-1)/(1/i-1) = 0
1/i + 1/i^2 .......+1/i^20 = 1/i(1/i^20-1)/(1/i-1)
since 1/i^20 = 1
thus sum = 1/i (1-1)/(1/i-1) = 0
Hrishu1:
You deserve Brainliest.
By the way 1/i is greater or less than 1
it is less than 1 since on rationalising u get -i
If it is less than 1 than the G.P should be a(1-r^n)/1-r
i think we cant say much
it doesn't matter u can take negative sign common from numerator and denominator than u will get same result
got it
bt in real we can say much about i less than one or greater than one coz its a complex no.
oh thank you
Hmm u really worth it robin
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