Math, asked by eufemiajeziagmailcom, 6 hours ago

evaluate the following using a suitable Identity (103)³​

Answers

Answered by ritadas70927
0

Step-by-step explanation:

((103)

3

=(100+3)

3

=(100)

3

+3

3

+3×100×3(100+3)

=1000000+27+90000+2700 =1092727

(99)

3

=(100−1)

3

=(100)

3

−1

3

−3×100×1(100−1)

=1000000−1−30000+300 =970299

Answered by ss8860104211
0

Answer:

by using identity

( a+b )³ = a³ + 3a²b + 3ab² + b³

(100+3)³ = (100)³ + (3×100)² × 3 + 3×100×(3)² + (3)³

= 1000000 + 9×10000 + 300×9 + 27

= 1000009 + 90000 + 2700 + 27

= 190000 + 2727

= 192727 (ans)

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