Question

evaluate the following using suilable identity. (-25)^3+10^3+15^3​

Answer 1

a=-25

b=10

c=15

a+b+c= -25+10+15=0

using identity

if a+b+c=0 then

a^3+b^3+c^3= 3abc

hence, -25^3+10^3+15^3=3×(-25)×10×15

=-75×150=-11250

Answer 2

Answer:

Ans= -11250

Step-by-step explanation:

from the given ingredients equ.ns

we know that...

→ (a)³+(b)³+(c)³ = 3abc

let's compare... to the RHS

THEN,

= 3×(-25)×(10)×(15)

= -11250

this'll be the ans.

I HOPE MAY THIS HELP YOU.