evaluate the following using suitable identies (10001)3
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Hey mate! Here's your answer:
Step-by-step explanation:
(10000 + 1)³
(a + b)³ = a³ + b³ + 3ab(a + b)
10000³ + 1³ + 3(10000)(1)(10000 + 1)
1000000000000 + 1 + (30000)(10001)
1000000000000 + 1 + 300030000
1000300030001.
So 10001³ = 1000300030001.
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