Question

Evaluate the following using suitable identites questions is (99) power 3​

Answer 1

Answer:

999999

Step-by-step explanation:

(100-1) ^3

(a-b) (a^2 + ab +b^2)

99(10000+100+1)

99×10101

999999

Answer 2

Answer:

970299

Step-by-step explanation:

Your question:

(99)³

You can also write as (100–1)³

You know that,

(a-b)³= a³–b³–3ab(a–b)

Taking a as 100 and b as 1

(100)³–(1)³–{3×100×1(100–1)}

1,000,000–1–(300×99)

1,000,000–1–29,700

999,999–29700

= 970,299