Question

evaluate the following using suitable identities 51 square​

Answer 1

$\boxed{\begin{minipage}{7 cm}Identity Used:- (a+b)^2 = a^2 + 2ab + b^2 \\ \\\end{minipage}}$

$\boxed{\begin{minipage}{7 cm}Evaluate:- (51)^2 \\ \\\end{minipage}}$

(51)² can be written as (50+1)²

By using the formula:-

(50+1)² = (50)² + (2) (50) (1) + (1)²

(50+1)² = 2500 + 100 + 1

(50+1)² = 2601

∴ Solution is 2601

Answer 2

Question:- Evaluate the following using suitable identities 51².

$\huge\mathcal\blue{Solution:-}$

• 51²= (50+1)²
• (a+b)² = a²+2ab+b²
• let, a= 50 , b=1
• 50²+2×50×1 + 1²
• 2500 + 100 + 1
• 2601

$\huge\mathcal\green{Answer= 2601}$

• Hope it helps
• Thanks
• Regards, AKASHITEMHEAVEN