Question

Evaluate the following using suitable identities
$({99}^3)$
$(102)^3$
$(998)^3$
$(1001)^3$




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Answer 1

Answer:

you can use the formula of ( a+b)³ &( a-b)³

1) (100-1)³

(100)³-(1)³-3(100*1)(100-11)

1000000-1-300(100-1)

1000000-1-30000+300

1000000-1-29700

970300-1

970299

2) (100+2)³

= (100)3 + (2)3 + 3(100)(2)(100 + 2)

= 1000000 + 8 + 600(100 + 2)

= 1000000 + 8 + 60000 + 1200

=1061208

3)(1000-2)³

= (1000)3 - (2)2 - 3( 1000)(2)( 1000 - 2)

= 1000000000 -8 - 6000(1000 - 2)

= 1000000000 - 8 - 6000000 + 12000

= 994011992.

4)(1000+1 )³

HOPE YOU CAN SOLE LAST ONE YOURSELF....