Question

Evaluate the following using suitable identity(1.01)*(1.01)

Answer 1

(1.01) × ( 1.01)

= ( 1.01)^2

= ( 1 + 0.01)^2

= (1)^2 + (0.01)^2 + 2(1)(0.01)

= 1 + 0.0001 + 0.02

= 1.0201

Answer 2

(1.01)^2
(1+.01)^2
(a+b)^2