Evaluate the following using suitable identity(1.01)*(1.01)
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(1.01) × ( 1.01)
= ( 1.01)^2
= ( 1 + 0.01)^2
= (1)^2 + (0.01)^2 + 2(1)(0.01)
= 1 + 0.0001 + 0.02
= 1.0201
= ( 1.01)^2
= ( 1 + 0.01)^2
= (1)^2 + (0.01)^2 + 2(1)(0.01)
= 1 + 0.0001 + 0.02
= 1.0201
sanjaydhanda123:
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(1.01)^2
(1+.01)^2
(a+b)^2
(1+.01)^2
(a+b)^2
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