Evaluate the following value.
If q(x)=x³+3x²+3x+1,findq(-2)+q(-3)+q(1/2)
Answers
Answered by
0
Answer:
q(-2)=(-2)³+3(-2)²+3(-2)+1
=(-8)+3(4)+(-6)+1
= -8+12-6+1
= 13-13
= 0
Step-by-step explanation:
q(-3)=(-3)³+3(-3)²+3(-3)+1
= -27 +3(9)+(-9)+1
= -27+27-9+1
=-9+1
=-8
Similar questions