Question

evaluate the following with suitable identity( 102)cube​

Answer 1

Answer:

14

Step-by-step explanation:

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Answer 2

Now using the identity (a+b) ^3 =a^ 3 +b^3+3ab(a+b),

we get(100+2)^3 =100^3 +2^3 +[(3×100×2)(100+2)]

=1000000+8+(600×102)

=1000000+8+61200

=1061208

Hence, (102) ^3=1061208