Math, asked by bip5791, 1 month ago

evaluate the following x = 4 10 + x² =

Answers

Answered by mrnickname50

$\huge[Answer]$

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⇒ 3x2−x−10=(x−2)(3x+5)

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)∴ Substituting it in the equation we get

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)∴ Substituting it in the equation we get x→2lim(x−2)(x+2)(x−2)(3x+5)

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)∴ Substituting it in the equation we get x→2lim(x−2)(x+2)(x−2)(3x+5)=x→2lim(x+2)(3x+5)

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)∴ Substituting it in the equation we get x→2lim(x−2)(x+2)(x−2)(3x+5)=x→2lim(x+2)(3x+5)Now substituting the limit we get,

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)∴ Substituting it in the equation we get x→2lim(x−2)(x+2)(x−2)(3x+5)=x→2lim(x+2)(3x+5)Now substituting the limit we get,=2+23(2)+5

⇒ 3x2−x−10=(x−2)(3x+5)⇒ x2−4=(x−2)(x+2)∴ Substituting it in the equation we get x→2lim(x−2)(x+2)(x−2)(3x+5)=x→2lim(x+2)(3x+5)Now substituting the limit we get,=2+23(2)+5=411

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