Question

Evaluate the function

Answer 1

Answer:

-17

0.45

Step-by-step explanation:

when x = -1

${ - 1}^{3} - (2 \times ( { - 1})^{2} )+( 6 \times - 1 )- 8$

$- 1 - 2 - 6 - 8$

$- 3 - 14$

$- 17ans$

when x= 1/4

${ (\frac{ 1}{4} })^{3} - (2 \times ({ \frac{ 1}{4}) }^{2} ) +( 6 \times \frac{ 1}{4} ) - 8$

$\frac{1}{64} - (2 \times \frac{1}{16} ) + \frac{6}{4} - 8$

$\frac{1}{64} - \frac{1}{8} + \frac{3}{2} - \frac{8}{1}$

$\frac{2-16+192-120}{128}$

$\frac{ -14+72 }{128}$

$\frac{ 58}{128}$

$0.45ans$