Evaluate the given algebraic expressions for x = 2, y = -3, z = 1, a = -4, b = -2 and c = 3. Hurry up its urgent please And don't post useless answers
Answers
Step-by-step explanation:
a) 3x-5y+2a
3*2-5*-3+2*-4
6+15-8
=13
b) x^3y+xy^2+xyz
(2)^3*-3+2*(-3)^2+2*-3*1
6-3+18+(-6)
3+18+(-6)
=15
c) a^2+ab+b^2
(-4)^2+(-4)*(-2)+(-2)^2
16+8+4
=28
d) 2xyz-3abc
(2*2*-3*1)(-3*-4*-2*3)
(-12)(12*-2*3)
(-12)(-72)
=854
e)-2x^2y+3yz^2+4x^2z^2
-2*(2)^2*-3+3*-3*(1)^2+4(2)^2*(1)^2
-2*4*-3+3*-3*1+4*4*1
24+(-9)+16
=31
f)a^2bc-4ab+2c
(-4)^2*-2*3-4*-4*-2+2*3
16*3+16*-2+6
28-32+6
=2
Answer:
a) 3x-5y+2x
Substituting x=2 y=-3 z=1
= 3×2-5×(-3)+2×1
=6+15+2
=23
b) x cube + xy square + xyz
Substituting x=2 y= -3 z=1
= 2 cube×(-3)+2×(-3) square+2×(-3)×1
= 8×(-3)+2×9-6
= -24+18-6
= -24-6+18
= -30+18
= -12
c) a square+ ab+b square
Substituting a= -4 b= -2 c= 3
=(-4) square+ (-4)×(-2)+(-2) square
= 16+8+4
= 28
d) 2xy-3ab
= 2×2×(-3)×1-3×(-4)×(-2)×3
= -12-72
= -84
e) -2x square y+3yz square+4x square z square
= -2×(2) square×(-3)+3×(-3)×(1) square+4×(2) square×(1) square
= -48-81+4096
= -129+4096
= 3867
f) a square bc-4ab+2c
= (-4) square×(-2)×3-4×(-4)×(-2)+2×3
= 16× -2×3-32+6
= -96-32+6
= -128+6
= -122
Step-by-step explanation:
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