Math, asked by poojadhari6753, 1 year ago

Evaluate the given definite trigonometric integral. A) Integral of d(theta)/2+cos(theta) from 0 to 2pi B) Integral of d(theta)/3+sin(theta)+cos(theta) from 0 to 2pi

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Answered by Anonymous
0
dx = x and. ∫ -3 cos 2x dx = -32 sin 2x are easy. The cos3 2x integral is like the .... Since u = arctan(x), -π/2 ≤ u ≤ π/2 and sec u ≥ 0, so .... EXAMPLE 10.3.2 Evaluate ∫ x sin x ...
Answered by Anonymous
0
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d/dx [definite integral from 0 to x of (2pi*u) du] is: a. 0 b. 1/2pi sin x c. sin(2pi x) d. cos (2pi x) e. 2pi cos (2pi x)

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