Math, asked by Gurleen713, 9 months ago

evaluate the given equation:(2y-1)(2y+1)(4y²+1)..

Answers

Answered by bhadrimahi

0

Answer:

[(2y-1 ) (2y+1)] (4y2 + 1)

(4y2-1)(4y2+1)

16y4 - 1

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