evaluate the given equation:(2y-1)(2y+1)(4y²+1)....
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hope it helps.... thanks
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use formula (a+b) (a-b) = a2-b2
therefore, (2y-) (2y+) = 4y2-1
and last step use formula again therefore, (4y2-1)(4y2+1)= 16y2-1.
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