Math, asked by jividhabadole, 10 months ago

Evaluate the given limit.​

Attachments:

Answers

Answered by rajsingh24
52

QUESTION:-

➟lim( x --> -2 ) = x ^7 +128 / x ³ + 8

SOLUTION:-

here apply L'HOSPITAL RULE.

➟lim( x --> -2 ) = (d/dx( x ^7 +128 )/ (d/dx(x ³ + 8))

➟lim( x --> -2 ) = ( 7x^6 / d/dx ( x³+8))

➟lim( x --> -2 ) = ( 7x^6 / 3x²)

➟lim( x --> -2 ) = ( 7x^4 / 3) ( x² cancel )

➟lim( x --> -2 ) = ( 7 × (-2)^4 / 3)

.°. lim(x---> -2 ) = 112/3 (ANSWER)

ALTERNATE FORM,

• 37. ⅓ or 37.3

Similar questions