Question

Evaluate the integral

∫1to 2 (4x^2-5x^2+6x+9)dx

Answer 1

QUESTION => ÉVALUATE INTEGRAL

$\int\limits^2_1$ (4x^2-5x^2 + 6x +9)

dx {4} [x^4/4] - 5 [x3/3] + 6 [x^2/2]. + 9 (X)

= x^4 - 5x^3/3 +3x^2 + 9x -F(X)

I = F(2)- F(1)

{ 2^4 - 5x (2^3)/3 + 3(2)^2 +9(2))} -{ (1)^4 - 5(1)^3/3 + 3(1)^2 +9(1) }

{ 16- 40/3 +12+ 18} - { 1-5/3 + 3 +9}

16- 40/3 + 12 + 18 - 1 + 5/3 -3 - 9

Taking LCM

WE WILL GET

33 - 35/3

33 x3 -35/3

= 99-35/3 = 64/3 ║