Math, asked by ooo2007, 7 months ago

Evaluate the integral ​

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Answered by sutharpraveena414
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Answered by sharoonaftab
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\int\limits {1/(sinxcos^2x)} \, dx \\simplify\\\int\ {secx^2/sinx} \, dx \\\int\limits {tan^2x+1/sinx} \, dx \\\int\ {sec(x)tan(x)} \, dx +\int\ {cscx} \, dx \\\int\ {secxtanx} \, dx =secx\\\int\ {cscx} \, dx =-ln(csc(x)+cotx)\\ put\\ the\\ values \\secx-ln(cscx+cotx)+c\\

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