evaluate the integral integration 0 to infinity, integration 0 to infinity e^-{x²+y²}dydx.by changing to polar coordinates
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Answer:
This is an old favorite of mine.
Define
I=∫
+∞
−∞
e−x2dx
Then
I2=(∫
+∞
−∞
e−x2dx)(∫
+∞
−∞
e−y2dy)
I2=∫
+∞
−∞
∫
+∞
−∞
e−(x2+y2)dxdy
Now change to polar coordinates
I2=∫
+2π
0
∫
+∞
0
e−r2rdrdθ
The θ integral just gives 2π, while the r integral succumbs to the substitution u=r2
I2=2π∫
+∞
0
e−udu/2=π
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