Question

evaluate the integral sin2x

Answer 1

you can see your answer

Answer 2

Given,

$let \ \ I = \int {\sin 2x} \, dx \\ \\ let \ 2x = t \\ \\ dx = \frac{dt}{2} \\ \\ So, \\ \\ I =\frac{1}2} \int {\sin t} \, dx \\ \\I = -\frac{1}{2}cost + c \\ \\ I = -\frac{1}{2}cos2x + c \ \ \textbf{Ans.}$