Evaluate the Integrals
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Answered by
4
Solution :
Let,
Taking differentials, we get

↬
As x tends to 4, z tends to 22
As x tends to 9, z tends to 3
Then,




Thus,
![\large{=\mathsf{[\frac{2}{3z}]_{22}^{3}}} \large{=\mathsf{[\frac{2}{3z}]_{22}^{3}}}](https://tex.z-dn.net/?f=%5Clarge%7B%3D%5Cmathsf%7B%5B%5Cfrac%7B2%7D%7B3z%7D%5D_%7B22%7D%5E%7B3%7D%7D%7D)




Let,
Taking differentials, we get
↬
As x tends to 4, z tends to 22
As x tends to 9, z tends to 3
Then,
Thus,
Answered by
1
Answer: 19/99
Step-by-step explanation:
Let,
Let,
Also,
When, x = 9 , t = 3
x = 4 , t = 22,
Now,
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