Evaluate the limit as x tends to infinity cosx+sinx/x2
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Given: lim cosx + sinx / x^2
x-->∞
To find: Solve the above expression.
Solution:
- Now we have given:
lim cosx + sinx / x^2
x-->∞
- Splitting it, we get:
= lim cosx / x^2 + lim sinx / x^2
x-->∞ x-->∞
- Considering cosx / x^2, we have:
= lim cosx / x^2 = 1 / 0 = ∞ ............(i)
x-->∞
- Considering sinx / x^2, we have:
= lim ( sinx / x )( 1/x )
x-->∞
= lim ( sinx / x ) . lim (1/x)
x-->∞ x-->∞
= 1 . 1/0 = ∞ ..............(ii)
- So from (i) and (ii), we get:
lim cosx + sinx / x^2 = +∞
x-->∞
Answer:
So the value of given term is +∞.
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