Math, asked by Stormer, 1 year ago

evaluate the limit . pls answer quickly

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Answered by Anonymous
2
limx→0 sinax/sinbx

we know lim x→0 sinx/x = 1

now multiply and divide by abx

we get
lim x→0 abxsinax/abxsinbx

now lim x→0 sinax/ax = 1
and lim x→0 bx/sinbx = 1


Thus lim x→0 abxsinax/abxsinbx
= a/b

Stormer: Thanks for the ans
Anonymous: no issues
Anonymous: you can ask more answers
Stormer: ok thanx
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