Question

Evaluate the limit$\lim_{x \to \4} ( \frac{4-x}{x^{2} -16} )$

Answer 1

Answer:

$\frac{-1}{8}$

Step-by-step explanation:

$</p><p>\lim_{x \rightarrow 4}{\frac{4-x}{x^2 -16}}\\</p><p>Apply \: L'Hospital:\\</p><p></p><p>=\lim_{x \to 4}{\frac{-1}{2x}}\\</p><p>\text{Put values}\\</p><p>=\frac{-1}{2(4)}\\</p><p>=\frac{-1}{8}$