Math, asked by kk1000, 1 month ago

Evaluate the limit ( x³ - 27 ) / ( |x-3| ) (x-3) when x tends to 3 negative .
Handwritten question is in attachment . ​

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Answers

Answered by smitikadas2006
22

Answer:

Because the limit of the denominator is not

0

, we can use substitution to evaluate the limit.

lim x → x3 + 27/ x + 3= (3³) + 27 /(3) + 3 =54/9 = 6

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