Evaluate the limit ( x³ - 27 ) / ( |x-3| ) (x-3) when x tends to 3 negative .
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Because the limit of the denominator is not
0
, we can use substitution to evaluate the limit.
lim x → x3 + 27/ x + 3= (3³) + 27 /(3) + 3 =54/9 = 6
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