Question

evaluate the question​

Answer 1

Answer:

16/3 is your answer pls Mark me as barinliest

Answer 2

Answer :-

$\rm \: The \: answer \: is \bf \: \dfrac{16}{3} or \: 5\dfrac{1}{3}$

Step-by-step-explaination :-

$\rm {\huge(} \dfrac{2}{3} {\huge)}^{ - 2} \times {\huge(} \dfrac{3}{2} {\huge)} ^{ - 3} \times { \huge(} \dfrac{ - 7}{8}{ \huge)}^{0}$

Now , the powers are negative but to solve them we have to make it positive . So, what to do to change the power's sign ? umm.. it is simple just flip the fraction (i.e. Make Denominator , Numerator and Numerator as Denominator) . And anything to the power of 0 refers to 1 .

${\tt \leadsto} \rm \rm {\huge(} \dfrac{3}{2} {\huge)}^{ 2} \times {\huge(} \dfrac{2}{3} {\huge)} ^{ 3} \times 1$

Now , expanding 3 two times and 2 times as well as 2 thrice and 3 also thrice. And 1 we multiple it .

(3×3×3/2×2) × (4×4×4/3×3×3) × 1

Now finding the value

${\tt \leadsto} \rm \rm \cancel \dfrac{9}{4} \times \cancel \dfrac{64}{27} = \dfrac{16}{3}$