Evaluate the question by complementary formulas.
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A+B+C=B+c=180-a
B+C\2=90-a/2
sin (b+c/2)=sin(90-a/2)
sin(b+c/2)=cos-a/2
hence prove
B+C\2=90-a/2
sin (b+c/2)=sin(90-a/2)
sin(b+c/2)=cos-a/2
hence prove
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