Question

evaluate the trignometry tan48 tan 23 tan 42 tan 67​

Answer 1

Answer:

$\color{purple}[ANSWER]$

=tan 48 tan 23 tan 42 tan 67

(tan90-thet =cos theta)

=cot (90-48) cot(90-23) tan42 tan67

=cot42 cot 67 tan42 tan67

( 1/cot theta=tan theta)

=1/tan42.tan42.1/tan67.tan67

=1 $\color{red}[ANSWER]$

I hope it's helpful for you

Answer 2

SOLUTION:-

$\implies \: \tan48 \degree \: \tan23 \degree \: \tan42 \degree \: \tan67 \degree \\ \\ \implies \: \tan48 \degree \tan23 \degree \tan (90 \degree - 48 \degree ) \tan(90 \degree - 23 \degree) \\ \\ \implies \: \tan48 \degree \: \cot 48 \degree \tan \: 23 \degree \cot23 \degree \\ \\ \implies \cancel{ \tan48 \degree \: \frac{1}{ \tan 48 \degree} \tan23 \degree \frac{1}{ \tan 23 \degree } } \\ \\ \implies \: 1$

uses concept:-

tan (90°-theta) =cot theta

tan theta=1/cot theta

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