Question

evaluate this........ ​

Answer 1

Answer:

Step-by-step explanation:

lim x tends to 0 sin ax+bx/ax+sinbx

divide the expression by x and multiply by x

sinax/x+bx/x/ax/x+sin bx/x

we know sin ax/a=a

sinbx/x=b

=a+b/a+b

=1

lim x tends to 0 ax+xcosx/bsinx

in this also divide the expression by x

a+cosx/b      sinx/x=1

substituting x=0 we get

a+1/b

for second question substitute x=0