Question

evaluate this . it's a maths question of class 9​

Answer 1

Answer:

P (x)=x^2-4x+3

p (2)=2^2-4 (2)+3

p(2)=4-8+3

p(2)=-1

p(-1)=(-1)^2-4 (-1)+3

p(-1)=1+4+3

p(-1)=8

p(1/2)=(1/2)^2- 4(1/2)+ 3

p(1/2)=1/4 - 2+3

p(1/2)=1/4 + 1

p (1/2)=5/4

p(2)-p (-1)+p (1/2)

=-1-8-5/4

=-9 - 5/4

=(-36-5)/4

=-41/4

Step-by-step explanation:

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Answer 2

Answer:

$p(x) = x ^{4} - 4x + 3 \\ then \: p(2) = 16 - 8 + 3 = 11 \\ p( - 1) = 1 + 4 + 3 = 8 \\ p( 1 \div 2) = 1 \div 16 - 2 + 3 = 17 \div 16$

THEN DO IT