Question

Evaluate this question​

Answer 1

Step-by-step explanation:

sorry don't know......

Answer 2

$\bf I=\int \frac{dx}{ {x}^{4} + 1}$

$\over { \underline{ \bf I = \frac{ \ln( \frac{{x}^{2} + \sqrt{2}x + 1}{ {x}^{2} - \sqrt{2}x + 1}) + 2( \arctan(1 + \sqrt{2}x) - \arctan(1 - \sqrt{2}x)) }{4 \sqrt{2} } + C }}$