Question

Evaluate this question ​

Answer 1

Answer:

Step-by-step explanation:

2 [  ( 1/root 2) ∧2  + ( root 3 ) ∧2 ]  -  6 [ ( root3 / 2) ∧2 - ( root 3 ) ∧2 ]  

÷ [ ( 1 / root 3 ) + ( 1 / root 3 ) ]

== 2 [ ( 1 / 2) + (3) ] - 6 [ ( 3/2 ) - ( 3 ) ] ÷ [ 2 / root 3 ]

== 2 [ 7/2 ] - 6 [ 9/2 ] ÷ [ 2 / root 3 ]

==  7 - 27 ÷ [ 2 / root 3 ]  

==  -20 ×  [  root 3 / 2 ]

==  - 10 × [ root 3 ]

==  -10$\sqrt{3}$

hope you got it ..