Question

evaluate this question bracket 2 upon 3 bracket ki power minus 2 into bracket 3 upon 4 bracket close - 3 power into bracket minus 7 upon it bracket close ki power 0​

Answer 1

(2/3)^-2×(3/4)^-3×(-7)^0

(3/2)^2×(4/3)^3×1

9/4×64/27

16/3

HOPE IT HELPS

Answer 2

Given that,

The equation is

$(\dfrac{2}{3})^{-2}\times(\dfrac{3}{4})^{-3}\times(-7)^{0}$

We need to evaluate this equation

Using given equation

$(\dfrac{2}{3})^{-2}\times(\dfrac{3}{4})^{-3}\times(-7)^{0}$

$(\dfrac{3}{2})^{2}\times(\dfrac{4}{3})^{3}\times(-7)^{0}$

$\dfrac{9}{4}\times\dfrac{64}{27}\times1$

$\dfrac{16}{3}$

Hence, The evaluate of this equation is $\dfrac{16}{3}$