Evaluate this sum polynomial
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HI there !
(a-b)² = a² -2ab + b²
a = 2x
b = 1/x
(2x - 1/x)² = (2x)² - 2 × 2x × 1/x + (1/x)²
= 4x² - 4x/x + 1/x²
(a-b)² = a² -2ab + b²
a = 2x
b = 1/x
(2x - 1/x)² = (2x)² - 2 × 2x × 1/x + (1/x)²
= 4x² - 4x/x + 1/x²
Answered by
1
Hey there !!!
(2x-1/x)²
given polynomial is of the form (a-b)²=a²-2ab+b²
So,
(2x-1/x)² = 4x²-2*2x*1/x+1/x²
=(4x²+1/x²-4)
=(4x²*x²-4x²+1)/x²
p(x)=(4x⁴-4x²+1)/x²
(2x-1/x)²
given polynomial is of the form (a-b)²=a²-2ab+b²
So,
(2x-1/x)² = 4x²-2*2x*1/x+1/x²
=(4x²+1/x²-4)
=(4x²*x²-4x²+1)/x²
p(x)=(4x⁴-4x²+1)/x²
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