Question

evaluate thr the following
[(64)⅔×2²+7⁰]-½
​

Answer 1

Step-by-step explanation:

[{(64)^1/3}^2×2^2+7^0]^-1/2

(4^2×2^2+1)^-1/2....as anything raise to power zero is 1

(16×4+1)^-1/2

According to BODMAS rule

(64+1)^-1/2

(65)^-1/2

√1/65

Answer 2

it may be hlep you . muje Patha nahi hai khi ye answer sahi hai ya galat